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0.215x-x^2=0.043^2
We move all terms to the left:
0.215x-x^2-(0.043^2)=0
We add all the numbers together, and all the variables
-1x^2+0.215x-0.001849=0
a = -1; b = 0.215; c = -0.001849;
Δ = b2-4ac
Δ = 0.2152-4·(-1)·(-0.001849)
Δ = 0.038829
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.215)-\sqrt{0.038829}}{2*-1}=\frac{-0.215-\sqrt{0.038829}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.215)+\sqrt{0.038829}}{2*-1}=\frac{-0.215+\sqrt{0.038829}}{-2} $
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